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1.2x^2-1.7x-0.6=0
a = 1.2; b = -1.7; c = -0.6;
Δ = b2-4ac
Δ = -1.72-4·1.2·(-0.6)
Δ = 5.77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.7)-\sqrt{5.77}}{2*1.2}=\frac{1.7-\sqrt{5.77}}{2.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.7)+\sqrt{5.77}}{2*1.2}=\frac{1.7+\sqrt{5.77}}{2.4} $
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